In the space below, algebraically solve the equation cos 3 x=0.5 in the domain -180^{circ} leq x leq 360^{circ}

Question

Accepted Answer

Step:1 ：Find the angles whose cosine is 0.5: (cos^{-1}(0.5) = 60^circ, 300^circ)Step:2 ：Divide the angles by 3 to get the values of x: (x_1 = frac{60^circ}{3} = 20^circ), (x_2 = frac{300^circ}{3} = 100^circ)Step:3 ：(boxed{x = 20^circ, 100^circ})

Answer

Step: 1 ：Find the angles whose cosine is 0.5: (cos^{-1}(0.5) = 60^circ, 300^circ)Step: 2 ：Divide the angles by 3 to get the values of x: (x_1 = frac{60^circ}{3} = 20^circ), (x_2 = frac{300^circ}{3} = 100^circ)Step: 3 ：(boxed{x = 20^circ, 100^circ})

In the space below, algebraically solve the equation $\cos 3 x = 0.5$ in the domain $- 180^{\circ} \leq x \leq 360^{\circ}$

Answer

Popular Problems

In the space below, algebraically solve the equation cos⁡3x=0.5 in the domain −180∘≤x≤360∘

Answer

Popular Problems

In the space below, algebraically solve the equation $\cos 3 x = 0.5$ in the domain $- 180^{\circ} \leq x \leq 360^{\circ}$