Solve this triangle.
\(C = 180^\circ - 30^\circ - 45^\circ = \boxed{105^\circ}\)
Step 1 :\(\cos A = \frac{(3 + \sqrt{3})^2 + (2 \sqrt{3})^2 - (\sqrt{6})^2}{2 (3 + \sqrt{3})(2 \sqrt{3})} = \frac{\sqrt{3}}{2}\)
Step 2 :\(A = \boxed{30^\circ}\)
Step 3 :\(\cos B = \frac{(3 + \sqrt{3})^2 + (\sqrt{6})^2 - (2 \sqrt{3})^2}{2 (3 + \sqrt{3})(\sqrt{6})} = \frac{1}{\sqrt{2}}\)
Step 4 :\(B = \boxed{45^\circ}\)
Step 5 :\(C = 180^\circ - 30^\circ - 45^\circ = \boxed{105^\circ}\)