Use substitution to determine whether 2 is a zero of the function.
\[
f(x)=x^{4}-2 x^{3}+2 x^{2}-7 x-6
\]
Is 2 a zero of $f(x)$ ?
Yes
No

Answer

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Answer

$\boxed{\text{No}}$

Steps

Step 1 ：Substitute x = 2 into the function $f(x) = x^{4} - 2x^{3} + 2x^{2} - 7x - 6$:

Step 2 ：$f(2) = 2^{4} - 2(2)^{3} + 2(2)^{2} - 7(2) - 6$

Step 3 ：$f(2) = 16 - 16 + 8 - 14 - 6$

Step 4 ：$f(2) = -12$

Step 5 ：Since $f(2) \neq 0$, 2 is not a zero of the function.

Step 6 ：$\boxed{\text{No}}$