Convert the rectangular coordinates (sqrt{3},-1) into polar form. Express the angle using radians in terms of pi over the interval 0 leq theta

Question

Convert the rectangular coordinates (sqrt{3},-1) into polar form. Express the angle using radians in terms of pi over the interval 0 leq theta<2 pi, with a positive value of r.

Accepted Answer

Step:1 ：Find the distance from the origin (r) using the formula: (r = sqrt{x^2 + y^2})Step:2 ：Find the angle (θ) using the arctangent function: (θ = arctan(frac{y}{x})) and make sure it is within the interval (0 leq θ < 2π)Step:3 ：The polar form of the rectangular coordinates ((sqrt{3},-1)) is (boxed{(2, frac{11pi}{6})})

Answer

Step: 1 ：Find the distance from the origin (r) using the formula: (r = sqrt{x^2 + y^2})Step: 2 ：Find the angle (θ) using the arctangent function: (θ = arctan(frac{y}{x})) and make sure it is within the interval (0 leq θ < 2π)Step: 3 ：The polar form of the rectangular coordinates ((sqrt{3},-1)) is (boxed{(2, frac{11pi}{6})})

Convert the rectangular coordinates $(\sqrt{3},-1)$ into polar form. Express the angle using radians in terms of $\pi$ over the interval $0 \leq \theta< 2 \pi$, with a positive value of $r$.

Answer

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