limx→04sinxsin2x2x3
Apply L'Hopital's rule and find the limit as x approaches 0: limx→04sin(x2)2cos(x)+4sin(x2)sin(x)cos(x2)3x2=1
Step 1 :Find the derivatives of the numerator and the denominator: ddx(4sinxsin2(x2))=4sin(x2)2cos(x)+4sin(x2)sin(x)cos(x2) and ddx(x3)=3x2
Step 2 :Apply L'Hopital's rule and find the limit as x approaches 0: limx→04sin(x2)2cos(x)+4sin(x2)sin(x)cos(x2)3x2=1