The length of a rectangle is ( 3 mathrm{~m} ) less than twice the width, and the area of the rectangle is ( 14 mathrm{~m}^{2} ). Find the dimensions of the rectangle.

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Accepted Answer

Step:1 ：1. Let width of rectangle be ( w mathrm{~m} ), so length ( = (2w - 3) mathrm{~m} ).Step:2 ：2. Area of rectangle is ( 14 mathrm{~m}^{2} ), so equation is ( w(2w - 3) = 14 ).Step:3 ：3. Solve quadratic equation ( 2w^2 - 3w - 14 = 0 ) with quadratic formula to get ( w approx 2.8823 mathrm{~m} ).Step:4 ：4. Calculate the length ( = (2w - 3) = (2(2.8823) - 3) approx 2.7646 mathrm{~m} ).Step:5 ：5. The dimensions of the rectangle are approximately ( 2.8823 mathrm{~m} ) width and ( 2.7646 mathrm{~m} ) length.

Answer

Step: 1 ：1. Let width of rectangle be ( w mathrm{~m} ), so length ( = (2w - 3) mathrm{~m} ).Step: 2 ：2. Area of rectangle is ( 14 mathrm{~m}^{2} ), so equation is ( w(2w - 3) = 14 ).Step: 3 ：3. Solve quadratic equation ( 2w^2 - 3w - 14 = 0 ) with quadratic formula to get ( w approx 2.8823 mathrm{~m} ).Step: 4 ：4. Calculate the length ( = (2w - 3) = (2(2.8823) - 3) approx 2.7646 mathrm{~m} ).Step: 5 ：5. The dimensions of the rectangle are approximately ( 2.8823 mathrm{~m} ) width and ( 2.7646 mathrm{~m} ) length.

The length of a rectangle is $3 m$ less than twice the width, and the area of the rectangle is $14 m^{2}$ . Find the dimensions of the rectangle.

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Popular Problems

The length of a rectangle is 3 m less than twice the width, and the area of the rectangle is 14 m2. Find the dimensions of the rectangle.

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Popular Problems

The length of a rectangle is $3 m$ less than twice the width, and the area of the rectangle is $14 m^{2}$ . Find the dimensions of the rectangle.