7 The solution to the equation \( 5 e^{x+2}=7 \) is
\( x=\ln{\frac{7}{5}}-2 \)
Step 1 :\( 5e^{x+2}=7 \)
Step 2 :\( e^{x+2}=\frac{7}{5} \)
Step 3 :\( x+2=\ln{\frac{7}{5}} \)
Step 4 :\( x=\ln{\frac{7}{5}}-2 \)