1) \( 2 \sqrt{5} V^{2}+2 \sqrt{5} \quad V=0 \)
2) \( f=\sqrt[3]{-64}+2 f, 3)|4 y+30|=7 \)

Answer

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Answer

2) Divide both sides by 3: \(f =\frac{\sqrt[3]{-64}}{3}\)

Steps

Step 1 ：1) Factor out \(2\sqrt{5}V\) from the equation: \( 2\sqrt{5} V^{2}+2\sqrt{5} V = 2\sqrt{5}V(V+1)=0 \)

Step 2 ：1) Separate each factor and solve for V: \(V=0\), \(V=-1\)

Step 3 ：2) Move the 2f to the other side: \(f = \sqrt[3]{-64} - 2f\)

Step 4 ：2) Add 2f to both sides: \(3f = \sqrt[3]{-64}\)

Step 5 ：2) Divide both sides by 3: \(f =\frac{\sqrt[3]{-64}}{3}\)