Problem

How many moles of nitrogen are in a \( 8 \mathrm{~L} \) container if the pressure is \( 66.6 \mathrm{~atm} \) and the temperature is \( 202.6^{\circ} \mathrm{C} \) ?

Answer

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Answer

\(n = \frac{66.6 \mathrm{~atm} \times 8 \mathrm{~L}}{0.0821 \frac{\mathrm{L\cdot atm}}{\mathrm{mol\cdot K}} \times (273.15 + 202.6)^{\circ} \mathrm{K}}\)

Steps

Step 1 ：\(PV = nRT\)

Step 2 ：\(n = \frac{PV}{RT}\)

Step 3 ：\(n = \frac{66.6 \mathrm{~atm} \times 8 \mathrm{~L}}{0.0821 \frac{\mathrm{L\cdot atm}}{\mathrm{mol\cdot K}} \times (273.15 + 202.6)^{\circ} \mathrm{K}}\)

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