Problem

4. \( 5 x^{2}-40 x=200 \)

Answer

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Answer

\(x = 2 \pm \sqrt{14}\)

Steps

Step 1 ：\(5x^{2} - 40x - 200 = 0\)

Step 2 ：\(x = \frac{-(-40) \pm \sqrt{(-40)^{2} - 4 \cdot 5 \cdot (-200)}}{2 \cdot 5}\)

Step 3 ：\(x = \frac{40 \pm \sqrt{1600 + 4000}}{10}\)

Step 4 ：\(x = \frac{40 \pm \sqrt{5600}}{10}\)

Step 5 ：\(x = \frac{40 \pm 20\sqrt{14}}{10}\)

Step 6 ：\(x = 2 \pm \sqrt{14}\)

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