What is the molecular weight of ( 28.5 mathrm{~g} ) of a gas which occupies ( 2.82 mathrm{~L} ) at ( 24.9 mathrm{~atm} ) and ( 436^{circ} mathrm{C} ) ?

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Step:1 ：Step 1: Calculate the number of moles using Ideal Gas Law: ( PV = nRT ), where ( P ) is pressure, ( V ) is volume, ( n ) is the number of moles, ( R ) is the ideal gas constant and ( T ) is temperature in Kelvin. Convert ( 436^{circ} mathrm{C} ) to Kelvin by adding 273.15: (436 + 273.15 = 709.15 mathrm{K})Step:2 ：Step 2: Solve for (n): ( n = frac{PV}{RT} ). Use ( P = 24.9 mathrm{~atm} ), ( V = 2.82 mathrm{~L} ), ( R = 0.0821 frac{mathrm{Lcdot atm}}{mathrm{molcdot K}} ), and ( T = 709.15 mathrm{K} ), then calculate (n)Step:3 ：Step 3: Calculate the molecular weight, (MW), using the mass and the number of moles: ( MW = frac{mass}{n} ). Use (mass = 28.5 mathrm{~g}) and the calculated value of (n), then find the (MW)

Answer

Step: 1 ：Step 1: Calculate the number of moles using Ideal Gas Law: ( PV = nRT ), where ( P ) is pressure, ( V ) is volume, ( n ) is the number of moles, ( R ) is the ideal gas constant and ( T ) is temperature in Kelvin. Convert ( 436^{circ} mathrm{C} ) to Kelvin by adding 273.15: (436 + 273.15 = 709.15 mathrm{K})Step: 2 ：Step 2: Solve for (n): ( n = frac{PV}{RT} ). Use ( P = 24.9 mathrm{~atm} ), ( V = 2.82 mathrm{~L} ), ( R = 0.0821 frac{mathrm{Lcdot atm}}{mathrm{molcdot K}} ), and ( T = 709.15 mathrm{K} ), then calculate (n)Step: 3 ：Step 3: Calculate the molecular weight, (MW), using the mass and the number of moles: ( MW = frac{mass}{n} ). Use (mass = 28.5 mathrm{~g}) and the calculated value of (n), then find the (MW)

What is the molecular weight of $28.5 g$ of a gas which occupies $2.82 L$ at $24.9 atm$ and $436^{\circ} C$ ?

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What is the molecular weight of 28.5 g of a gas which occupies 2.82 L at 24.9 atm and 436∘C ?

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Popular Problems

What is the molecular weight of $28.5 g$ of a gas which occupies $2.82 L$ at $24.9 atm$ and $436^{\circ} C$ ?