Problem

$\frac{c^{2}+6 c+8}{c^{2}-5 c-14} ?$

Answer

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Answer

Simplify the expression: \(\boxed{\frac{c+4}{c-7}}\)

Steps

Step 1 ：Factor the numerator and denominator: \(\frac{(c+2)(c+4)}{(c-7)(c+2)}\)

Step 2 ：Simplify the expression: \(\boxed{\frac{c+4}{c-7}}\)

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