The final velocity, $V$, of an object under constant acceleration can be found using the formula $V^{2}=v^{2}+2 a s$, where $v$ is the initial velocity (in meters per second), $a$ is acceleration (in meters per second), and $s$ is the distance (in meters). What is the formula solved for $a$ ?
$v^{2}-v^{2}-2 s=a$
$v^{2}-v^{2}+2 s=a$
$\frac{v^{2}-v^{2}}{2 s}=a$
$\frac{v^{2}+v^{2}}{2 s}=a$
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Answer

Divide both sides by $2s$: $a = \boxed{\frac{V^2 - v^2}{2s}}$

Steps

Step 1 ：Subtract $v^2$ from both sides: $V^2 - v^2 = 2as$

Step 2 ：Divide both sides by $2s$: $a = \boxed{\frac{V^2 - v^2}{2s}}$