The final velocity, $V$, of an object under constant acceleration can be found using the formula $V^{2}=v^{2}+2 a s$, where $V$ the initial velocity (in meters per second), $a$ is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for $a$ ?
$v^{2}-v^{2}-2 s=a$
$v^{2}-v^{2}+2 s=a$
$\frac{v^{2}-v^{2}}{2 s}=a$
$\frac{v^{2}+v^{2}}{2 s}=a$

Compute $\int_{0}^{\ln (2) / … Solve the triangle. \[ \mathr… QUESTION 2 - 1 POINT Solve th… 5. Suppose you are a computer… Answer the statistical measur… $(-\infty, 2) \cap(-6, \infty… A firm does not pay a dividen… Math 112 Section: 4. Tubercul… Find $y^{\prime}$ if $y=\ln \… 3. (3pts) Cherry trees in a c… More