Problem

Write a recursive formula for \( a_{n} \), the \( n^{\text {th }} \) term of the sequence \( 1,6,36,216, \ldots \)
\( a_{1}= \)
\( a_{n}= \)
Submit Answer
\( a_{n-1} \)

Answer

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Answer

\(a_{n}=6a_{n-1}\)

Steps

Step 1 :\(a_{1}=1\)

Step 2 :\(a_{n}=6a_{n-1}\)

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