Write a recursive formula for \( a_{n} \), the \( n^{\text {th }} \) term of the sequence \( 1,6,36,216, \ldots \)\( a_{1}= \)\( a_{n}= \)Submit Answer\( a_{n-1} \)
\(a_{n}=6a_{n-1}\)
Step 1 :\(a_{1}=1\)
Step 2 :\(a_{n}=6a_{n-1}\)