Select the equivalent expression.
${(\frac{d^{6}}{d^{- 7}})}^{\frac{4}{39}}$
$\frac{1}{\sqrt[4]{d^{3}}}$
$\sqrt[3]{d^{4}}$
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$\frac{1}{\sqrt[3]{d^{4}}}$
$\sqrt[4]{d^{3}}$

Answer

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Answer

$= d^{\frac{52}{39}}$

Steps

Step 1 ： ${(\frac{d^{6}}{d^{- 7}})}^{\frac{4}{39}} = {(d^{(6 + 7)})}^{\frac{4}{39}}$

Step 2 ： $= {(d^{13})}^{\frac{4}{39}}$

Step 3 ： $= d^{\frac{52}{39}}$