The weight of oranges growing in an orchard is normally distributed with a mean weight of ( 8 mathrm{oz} ). and a standard deviation of ( 0.5 mathrm{oz} ). What is the probability that a randomly selected orange from the orchard weighs more than ( 8 mathrm{oz} ), to the nearest thousandth?

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Step:1 ：Step 1: Calculate the z-score: (z = frac{x - mu}{sigma})Step:2 ：Step 2: Find the area to the left of the z-score using a z-tableStep:3 ：Step 3: Calculate the probability: (P(X > x) = 1 - P(X le x))

Answer

Step: 1 ：Step 1: Calculate the z-score: (z = frac{x - mu}{sigma})Step: 2 ：Step 2: Find the area to the left of the z-score using a z-tableStep: 3 ：Step 3: Calculate the probability: (P(X > x) = 1 - P(X le x))

The weight of oranges growing in an orchard is normally distributed with a mean weight of \( 8 \mathrm{oz} \). and a standard deviation of \( 0.5 \mathrm{oz} \). What is the probability that a randomly selected orange from the orchard weighs more than \( 8 \mathrm{oz} \), to the nearest thousandth?

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