$\begin{array}{l}10 \frac{7}{10}-3 \frac{1}{2}=\frac{}{A} \\ 7 \frac{2}{3}-2 \frac{7}{12}=\frac{}{P} \\ 12 \frac{1}{2}-5 \frac{1}{10}=\frac{}{F} \\ 4 \frac{5}{8}-3 \frac{3}{4}=\frac{L}{H} \\ 11 \frac{5}{8}-5 \frac{1}{3}=\frac{H}{4} \\ 4 \frac{3}{4}-2 \frac{1}{10}=\frac{G}{F}\end{array}$
Answer
Final Answer: \(\boxed{\frac{36}{5}}\) (A), \(\boxed{\frac{61}{12}}\) (P), \(\boxed{\frac{37}{5}}\) (F), \(\boxed{\frac{7}{8}}\) (L/H), \(\boxed{\frac{151}{24}}\) (H/4), \(\boxed{\frac{53}{20}}\) (G/F)
Step 1 ：Convert mixed numbers to improper fractions and subtract them: \(\frac{36}{5}\), \(\frac{61}{12}\), \(\frac{37}{5}\), \(\frac{7}{8}\), \(\frac{151}{24}\), \(\frac{53}{20}\)
Step 2 ：Final Answer: \(\boxed{\frac{36}{5}}\) (A), \(\boxed{\frac{61}{12}}\) (P), \(\boxed{\frac{37}{5}}\) (F), \(\boxed{\frac{7}{8}}\) (L/H), \(\boxed{\frac{151}{24}}\) (H/4), \(\boxed{\frac{53}{20}}\) (G/F)
