In a system the pressure and mass are kept constant. The initial temperature of the system is ( -48.5^{circ} mathrm{C} ). If the temperature changes to ( 119.8^{circ} mathrm{C} ) as the volume becomes ( 6.43 mathrm{~L} ), what was the initial volume?

Question

Accepted Answer

Step:1 ：Convert initial and final temperatures to Kelvin: (T_1 = -48.5 + 273.15 = 224.65 K), (T_2 = 119.8 + 273.15 = 392.95 K).Step:2 ：Apply the formula for constant pressure temperature-volume relation: (frac{V_1}{T_1} = frac{V_2}{T_2}).Step:3 ：Solve for initial volume (V_1): (V_1 = frac{V_2 times T_1}{T_2} = frac{6.43 L times 224.65 K}{392.95 K} = 3.6984 L).

Answer

Step: 1 ：Convert initial and final temperatures to Kelvin: (T_1 = -48.5 + 273.15 = 224.65 K), (T_2 = 119.8 + 273.15 = 392.95 K).Step: 2 ：Apply the formula for constant pressure temperature-volume relation: (frac{V_1}{T_1} = frac{V_2}{T_2}).Step: 3 ：Solve for initial volume (V_1): (V_1 = frac{V_2 times T_1}{T_2} = frac{6.43 L times 224.65 K}{392.95 K} = 3.6984 L).

In a system the pressure and mass are kept constant. The initial temperature of the system is $- {48.5}^{\circ} C$ . If the temperature changes to ${119.8}^{\circ} C$ as the volume becomes $6.43 L$ , what was the initial volume?

Answer

Popular Problems

In a system the pressure and mass are kept constant. The initial temperature of the system is −48.5∘C. If the temperature changes to 119.8∘C as the volume becomes 6.43 L, what was the initial volume?

Answer

Popular Problems

In a system the pressure and mass are kept constant. The initial temperature of the system is $- {48.5}^{\circ} C$ . If the temperature changes to ${119.8}^{\circ} C$ as the volume becomes $6.43 L$ , what was the initial volume?