In a system the temperature and mass are kept constant. The initial pressure of the system is ( 20 mathrm{~atm} ) and the volume is ( 0.23 mathrm{~L} ). If the pressure changes to 1.05 atm what is the volume?

Question

Accepted Answer

Step:1 ：(1. ) Use Boyle&#x27;s Law: (P_1V_1 = P_2V_2)Step:2 ：(2. ) Substitute values: (20 mathrm{~atm} times 0.23 mathrm{~L} = 1.05 mathrm{~atm} times V_2)Step:3 ：(3. ) Solve for (V_2): (V_2 = frac{20 mathrm{~atm} times 0.23 mathrm{~L}}{1.05 mathrm{~atm}} approx 4.3810 mathrm{~L} )

Answer

Step: 1 ：(1. ) Use Boyle&#x27;s Law: (P_1V_1 = P_2V_2)Step: 2 ：(2. ) Substitute values: (20 mathrm{~atm} times 0.23 mathrm{~L} = 1.05 mathrm{~atm} times V_2)Step: 3 ：(3. ) Solve for (V_2): (V_2 = frac{20 mathrm{~atm} times 0.23 mathrm{~L}}{1.05 mathrm{~atm}} approx 4.3810 mathrm{~L} )

In a system the temperature and mass are kept constant. The initial pressure of the system is $20 atm$ and the volume is $0.23 L$ . If the pressure changes to 1.05 atm what is the volume?

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Popular Problems

In a system the temperature and mass are kept constant. The initial pressure of the system is 20 atm and the volume is 0.23 L. If the pressure changes to 1.05 atm what is the volume?

Answer

Popular Problems

In a system the temperature and mass are kept constant. The initial pressure of the system is $20 atm$ and the volume is $0.23 L$ . If the pressure changes to 1.05 atm what is the volume?