Problem

In a system the temperature and mass are kept constant. The initial pressure of the system is \( 20 \mathrm{~atm} \) and the volume is \( 0.23 \mathrm{~L} \). If the pressure changes to 1.05 atm what is the volume?

Answer

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Answer

\(3. \) Solve for \(V_2\): \(V_2 = \frac{20 \mathrm{~atm} \times 0.23 \mathrm{~L}}{1.05 \mathrm{~atm}} \approx 4.3810 \mathrm{~L} \)

Steps

Step 1 ：\(1. \) Use Boyle's Law: \(P_1V_1 = P_2V_2\)

Step 2 ：\(2. \) Substitute values: \(20 \mathrm{~atm} \times 0.23 \mathrm{~L} = 1.05 \mathrm{~atm} \times V_2\)

Step 3 ：\(3. \) Solve for \(V_2\): \(V_2 = \frac{20 \mathrm{~atm} \times 0.23 \mathrm{~L}}{1.05 \mathrm{~atm}} \approx 4.3810 \mathrm{~L} \)

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