Paige has some cards. Each card has a colour on it.
If she chooses a card at random, then
\[
P(\text { blue })=\frac{5}{9} \text { and } P(\text { white })=\frac{1}{18} \text {. }
\]
Calculate $P$ (neither blue nor white).
Give your answer as a fraction in its simplest form.

Answer

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Answer

Simplify the expression: $\boxed{\frac{7}{18}}$

Steps

Step 1 ：Since the total probability of all possible outcomes is 1, we can subtract the probabilities of choosing a blue card and a white card from 1 to find the probability of choosing a card that is neither blue nor white: $1 - \frac{5}{9} - \frac{1}{18}$

Step 2 ：Simplify the expression: $\boxed{\frac{7}{18}}$

Paige has some cards. Each card has a colour on it.If she chooses a card at random, then\[P(\text { blue })=\frac{5}{9} \text { and } P(\text { white })=\frac{1}{18} \text {. }\]Calculate $P$ (neither blue nor white).Give your answer as a fraction in its simplest form.

Answer

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Paige has some cards. Each card has a colour on it.
If she chooses a card at random, then
\[
P(\text { blue })=\frac{5}{9} \text { and } P(\text { white })=\frac{1}{18} \text {. }
\]
Calculate $P$ (neither blue nor white).
Give your answer as a fraction in its simplest form.