10 Consider the quadratic equation below:
\[
5 x^{2}+12 x-216
\]
Part A
What are the values of $a, b$, and $c$ ?
\[
\begin{array}{l}
a=5 \\
b=12 \\
c=-216
\end{array}
\]
Part B
What is the axis of symmetry? (Write your answer as a DECIMAL!)
\[
\boldsymbol{x}=
\]

Answer

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Answer

Part B: $\text{Axis of symmetry: } x = -1.2$

Steps

Step 1 ：Given the quadratic equation: $5x^2 + 12x - 216$

Step 2 ：Identify the coefficients: $a = 5, b = 12, c = -216$

Step 3 ：Find the axis of symmetry using the formula: $x = \frac{-b}{2a}$

Step 4 ：Substitute the values of a and b: $x = \frac{-12}{2 \times 5}$

Step 5 ：Simplify the expression: $x = -1.2$

Step 6 ：$\boxed{\text{Final Answer:}}$

Step 7 ：Part A: $a = 5, b = 12, c = -216$

Step 8 ：Part B: $\text{Axis of symmetry: } x = -1.2$