Given the matrices \( A \) and \( B \) shown below, find \( -\frac{1}{2} B-3 A \).
\[
A=\left[\begin{array}{cc}
4 & 6 \\
-4 & 3
\end{array}\right] \quad B=\left[\begin{array}{cr}
12 & -6 \\
24 & -8
\end{array}\right]
\]

Answer

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Answer

\(-\frac{1}{2} B - 3 A = \left[\begin{array}{cc} (-6) + (-12) & 3+(-18)\\(-12)+12 & 4+(-9)\end{array}\right] = \left[\begin{array}{cc} -18 & -15\\0 & -5\end{array}\right]\)

Steps

Step 1 ：\(-\frac{1}{2} B = \left[\begin{array}{cc}-6 & 3\\-12 & 4\end{array}\right]\)

Step 2 ：\(-3 A = \left[\begin{array}{cc} -12 & -18\\12 & -9\end{array}\right]\)

Step 3 ：\(-\frac{1}{2} B - 3 A = \left[\begin{array}{cc} (-6) + (-12) & 3+(-18)\\(-12)+12 & 4+(-9)\end{array}\right] = \left[\begin{array}{cc} -18 & -15\\0 & -5\end{array}\right]\)

Given the matrices \( A \) and \( B \) shown below, find \( -\frac{1}{2} B-3 A \).\[A=\left[\begin{array}{cc}4 & 6 \\-4 & 3\end{array}\right] \quad B=\left[\begin{array}{cr}12 & -6 \\24 & -8\end{array}\right]\]

Answer

Popular Problems

Given the matrices \( A \) and \( B \) shown below, find \( -\frac{1}{2} B-3 A \).
\[
A=\left[\begin{array}{cc}
4 & 6 \\
-4 & 3
\end{array}\right] \quad B=\left[\begin{array}{cr}
12 & -6 \\
24 & -8
\end{array}\right]
\]