A child's game uses the spinner shown.
What is the probability that in two consecutive spins, the first outcome is red and the second outcome is blue?
\( \frac{1}{2} \)
\( \frac{1}{4} \)
\( \frac{1}{12} \)
\( \frac{1}{16} \)

Answer

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Answer

\( P(\text{Red and Blue}) = \frac{1}{2} \times\frac{1}{4} = \frac{1}{8} \)

Steps

Step 1 ：\( P(\text{Red}) = \frac{1}{2} \)

Step 2 ：\( P(\text{Blue}) = \frac{1}{4} \)

Step 3 ：\( P(\text{Red and Blue}) = \frac{1}{2} \times\frac{1}{4} = \frac{1}{8} \)