( left[frac{1+i}{1-i}right]^{r}+frac{1}{x+i y}=1+i )

Question

Accepted Answer

Step:1 ：( (1+i)^{r}(1-i)^{-r}+frac{1}{x+iy} = 1+i )Step:2 ：Considering ( r = 1, x = frac{1}{2}, y = frac{1}{2} )Step:3 ：( frac{2i}{2} = 1+i )

Answer

Step: 1 ：( (1+i)^{r}(1-i)^{-r}+frac{1}{x+iy} = 1+i )Step: 2 ：Considering ( r = 1, x = frac{1}{2}, y = frac{1}{2} )Step: 3 ：( frac{2i}{2} = 1+i )

\( \left[\frac{1+i}{1-i}\right]^{r}+\frac{1}{x+i y}=1+i \)