Lesson 3: Equation of a straight line
Syllabus Outcome:
Review the linear function $y=m x+c$ and understand the ge
Edrolo video: https://edrolo.com.au/class/1181362/lesson/38030/1
Equation of a straight line:
\[
y=m x+c
\]
*Note $c$ is sometimes referred to as $b$ *
Example 1:
Write the equation of a straight line with:
a. Gradient of -1 and $y$-intercept of 4
b. Gradient of $\frac{3}{4}$ and $y$-intercept of $-\frac{1}{2}$
Challenge:
Rewrite $b$ without fractions.
Answer
\(\boxed{\text{Final Answer:}}\) \(\boxed{\text{a. }} y = -1x + 4\) \(\boxed{\text{b. }} y = \frac{3}{4}x - \frac{1}{2}\)
Step 1 ：For part a, we have a gradient of -1 and a y-intercept of 4. We can use the equation of a straight line, y = mx + c, and plug in the given values to find the equation: \(y = -1x + 4\)
Step 2 ：For part b, we have a gradient of \(\frac{3}{4}\) and a y-intercept of \(-\frac{1}{2}\). We can use the equation of a straight line, y = mx + c, and plug in the given values to find the equation: \(y = \frac{3}{4}x - \frac{1}{2}\)
Step 3 ：\(\boxed{\text{Final Answer:}}\) \(\boxed{\text{a. }} y = -1x + 4\) \(\boxed{\text{b. }} y = \frac{3}{4}x - \frac{1}{2}\)
