Problem

A certain television is advertised as a 63-inch TV (the diagonal length). If the height of the TV is 43 inches, how wide is the TV? Round to the nearest tenth of an inch.

Answer

Expert–verified
Hide Steps
Answer

\( W \approx \sqrt{63^2 - 43^2} \)

Steps

Step 1 ：\( W^2 + 43^2 = 63^2 \)

Step 2 ：\( W^2 = 63^2 - 43^2 \)

Step 3 ：\( W \approx \sqrt{63^2 - 43^2} \)

link_gpt

Popular Problems

Compute $\int_{0}^{\ln (2) / … Solve the triangle. \[ \mathr… QUESTION 2 - 1 POINT Solve th… 5. Suppose you are a computer… Answer the statistical measur… $(-\infty, 2) \cap(-6, \infty… A firm does not pay a dividen… Math 112 Section: 4. Tubercul… Find $y^{\prime}$ if $y=\ln \… 3. (3pts) Cherry trees in a c… More