Write the first four terms of the sequence whose general term is given below.
\[
a_{n}=4(n+1) !
\]
Final Answer: The first four terms of the sequence are \(\boxed{4, 8, 24, 96}\).
Step 1 :The general term of the sequence is given by \(a_{n}=4(n+1) !\). This means that to find the nth term of the sequence, we need to substitute n into the formula and calculate the factorial of \((n+1)\), then multiply the result by 4.
Step 2 :To find the first four terms, we substitute n = 0, 1, 2, 3 into the formula.
Step 3 :The first four terms of the sequence are \(4, 8, 24, 96\).
Step 4 :Final Answer: The first four terms of the sequence are \(\boxed{4, 8, 24, 96}\).