11 point
Jackson is rewriting a fraction in lowest terms. Which value is missing?
\[
\frac{36 \div ?}{42 \div ?}=\frac{6}{7}
\]
7
6
4

Step 1 ：Notice that the fraction can be simplified by dividing both the numerator and the denominator by the same number.

Step 2 ：Let's denote this number as \(x\). So, we have \(\frac{36 \div x}{42 \div x}=\frac{6}{7}\).

Step 3 ：Cross-multiplying gives \(36 \times 7 = 42 \times 6 \times x\).

Step 4 ：Solving for \(x\) gives \(x = \frac{36 \times 7}{42 \times 6}\).

Step 5 ：Simplifying the right side of the equation gives \(x = \frac{6 \times 7}{6 \times 7}\).

Step 6 ：So, \(x = 1\).

Step 7 ：But 1 is not in the options, so we must have made a mistake.

Step 8 ：Let's try to simplify the fraction \(\frac{36}{42}\) to see if we can find a clue.

Step 9 ：We find that \(\frac{36}{42} = \frac{6 \times 6}{6 \times 7}\), which simplifies to \(\frac{6}{7}\).

Step 10 ：So, the missing value is \(x = 6\), which is in the options.

Step 11 ：Thus, the missing value is \(\boxed{6}\).