Problem

8
1 point
Cheng had submarine sandwich that was $5 \frac{7}{8}$ feet long delivered for his birthday party. If $3 \frac{3}{5}$ feet of the sandiwich was eaten, how many feet of the sandwich was left?
a. $1 \frac{11}{40}$
c. $2 \frac{9}{40}$
b. $2 \frac{11}{40}$
d. $2 \frac{4}{3}$
The answer is choose your answer...

Answer

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Answer

\(\boxed{2 \frac{11}{40}}\) feet of the sandwich was left.

Steps

Step 1 :Convert the mixed numbers to improper fractions. The initial length of the sandwich is \(5 \frac{7}{8}\) feet, which is \(\frac{47}{8}\) feet. The eaten length is \(3 \frac{3}{5}\) feet, which is \(\frac{18}{5}\) feet.

Step 2 :Subtract the two fractions to find the remaining length of the sandwich. \(\frac{47}{8} - \frac{18}{5} = \frac{111}{40}\) feet.

Step 3 :Convert the improper fraction back to a mixed number. \(\frac{111}{40} = 2 \frac{11}{40}\) feet.

Step 4 :\(\boxed{2 \frac{11}{40}}\) feet of the sandwich was left.

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