Problem

24. A 15,000-kg truck moves up an inclined plane at a constant speed of $10 \mathrm{~m} / \mathrm{s}$. If, the plane makes an angle of $30^{\circ}$ with the horizontal, what is the horsepower required to move the truck? Use $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$.
(a) $2000 \mathrm{hp}$
b) $200 \mathrm{hp}$
c) $100 \mathrm{hp}$
(d) $1000 \mathrm{hp}$
25 . A car starts from rest and after 6.0 seconds it has a kinetic energy of $60,000 \mathrm{~J}$. How much horsepower is needed for the car to acquire this kinetic energy?
a) $60 \mathrm{hp}$
b) 0
c) $1.34 \mathrm{hp}$
(d) $13.4 \mathrm{hp}$

Answer

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Answer

Final Answer: The horsepower required to move the truck is approximately \(\boxed{1005 \, hp}\).

Steps

Step 1 :Given that the mass of the truck is 15,000 kg, it moves at a constant speed of 10 m/s, and the plane makes an angle of 30 degrees with the horizontal. We are asked to find the horsepower required to move the truck.

Step 2 :First, we need to calculate the force exerted by the truck. This can be done using the formula for force, which is the weight of the truck times the sine of the angle of the incline. The weight of the truck is its mass times gravity, which is 15,000 kg times 10 m/s^2. The sine of 30 degrees is 0.5. Therefore, the force exerted by the truck is \(15000 \times 10 \times 0.5 = 75000 \, N\).

Step 3 :Next, we calculate the work done by the truck. The work done is equal to the force times the distance. The distance is the speed of the truck times the time. Since the truck is moving at a constant speed, we can assume that the time is 1 second. Therefore, the work done by the truck is \(75000 \times 10 = 750000 \, J\).

Step 4 :Then, we calculate the power required to do this work. Power is equal to work divided by time. Since we assumed that the time is 1 second, the power required is \(750000 \, J / 1 \, s = 750000 \, W\).

Step 5 :Finally, we convert the power from watts to horsepower. 1 horsepower is equal to 746 watts. Therefore, the horsepower required to move the truck is \(750000 \, W / 746 = 1005 \, hp\).

Step 6 :Final Answer: The horsepower required to move the truck is approximately \(\boxed{1005 \, hp}\).

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