Problem

17) $\frac{43-1}{4+2}+10$

Answer

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Answer

\(\boxed{17}\)

Steps

Step 1 ：1. Subtract 1 from 43: \(43 - 1 = 42\)

Step 2 ：2. Add 4 and 2: \(4 + 2 = 6\)

Step 3 ：3. Divide the result of step 1 by the result of step 2: \(\frac{42}{6} = 7\)

Step 4 ：4. Add 10 to the result of step 3: \(7 + 10 = 17\)

Step 5 ：\(\boxed{17}\)

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