The population (in thousands) of people of a city is approximated by the function $P(t)=1100(2)$ ) $0.1031 t$, where $t$ is the number of years since 2011 .
a. Find the population of this group in 2018.
b. Predict the population in 2028 .
a. The population of this group in 2018 is 1814000 .
(Round to the nearest thousand as needed.)
b. The predicted population in 2028 is

Step 1 ：The population (in thousands) of people of a city is approximated by the function \(P(t)=1100(2)^{0.1031 t}\), where \(t\) is the number of years since 2011.

Step 2 ：To find the population of this group in 2018, we need to substitute the value of \(t\) into the function \(P(t)\). The number of years from 2011 to 2018 is 7, so we substitute \(t=7\) into the function.

Step 3 ：Calculating \(P(7)\) gives us approximately 1814.036549423391 (in thousands). Rounding to the nearest thousand gives us 1814000.

Step 4 ：The final population of this group in 2018 is therefore approximately \(\boxed{1814000}\).

Step 5 ：To predict the population in 2028, we again substitute the value of \(t\) into the function \(P(t)\). The number of years from 2011 to 2028 is 17, so we substitute \(t=17\) into the function.

Step 6 ：Calculating \(P(17)\) gives us approximately 3706.8751466472654 (in thousands). Rounding to the nearest thousand gives us 3707000.

Step 7 ：The predicted population in 2028 is therefore approximately \(\boxed{3707000}\).