Problem

a. Suppose that $f$ is a monomial function such that as $x \rightarrow \infty, f(x) \rightarrow-\infty$. Which of the following could be a function formula for $f$ ? Select all that apply.
\[
\begin{array}{l}
f(x)=-\left(\frac{1}{7}\right) x^{4} \\
f(x)=-3 x^{2} \\
f(x)=5.5 x^{5} \\
f(x)=x^{10} \\
f(x)=-x^{9}
\end{array}
\]
b. Suppose $g$ is a monomial function such that as $x \rightarrow \infty, g(x) \rightarrow \infty$ and as $x \rightarrow-\infty, g(x) \rightarrow \infty$. Which of the following could be a function formula for $f$ ? Select all that apply.
\[
\begin{array}{l}
\square(x)=-2 x^{2} \\
\square(x)=x^{8} \\
\square f(x)=\left(\frac{1}{5}\right) x^{4} \\
\square f(x)=-\left(\frac{1}{2}\right) x^{3} \\
\square f(x)=x^{5}
\end{array}
\]

Answer

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Answer

Final Answer: \(\boxed{f(x)=-\left(\frac{1}{7}\right) x^{4}, f(x)=-3 x^{2}, f(x)=-x^{9}}\)

Steps

Step 1 :Given that $f$ is a monomial function such that as $x \rightarrow \infty, f(x) \rightarrow -\infty$. This implies that the function must have an odd degree and a negative coefficient.

Step 2 :By substituting a large value of $x$ into each function, we can determine which functions tend towards negative infinity as $x$ tends towards infinity.

Step 3 :For $f(x)=-\left(\frac{1}{7}\right) x^{4}$, $f(x)=-3 x^{2}$, and $f(x)=-x^{9}$, the results are negative for a large $x$, which means they tend towards negative infinity as $x$ tends towards infinity.

Step 4 :For $f(x)=5.5 x^{5}$ and $f(x)=x^{10}$, the results are positive for a large $x$, which means they tend towards positive infinity as $x$ tends towards infinity.

Step 5 :Therefore, the function formulas for $f$ could be $f(x)=-\left(\frac{1}{7}\right) x^{4}$, $f(x)=-3 x^{2}$, and $f(x)=-x^{9}$.

Step 6 :Final Answer: \(\boxed{f(x)=-\left(\frac{1}{7}\right) x^{4}, f(x)=-3 x^{2}, f(x)=-x^{9}}\)

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