If sin x=-1 and x in[0,2 pi], the value of x is

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Step:1 ：Given the equation (sin x = -1) with (x in [0,2 pi]).Step:2 ：The sine function reaches its minimum value of -1 at (x = frac{3pi}{2}) in the interval ([0, 2pi]).Step:3 ：Therefore, the value of (x) that satisfies the equation (sin x = -1) is (x = frac{3pi}{2}).Step:4 ：Converting (frac{3pi}{2}) to decimal form gives approximately 4.71238898038469.Step:5 ：Final Answer: The value of (x) that satisfies the equation (sin x = -1) in the interval ([0, 2pi]) is (boxed{frac{3pi}{2}}).

Answer

Step: 1 ：Given the equation (sin x = -1) with (x in [0,2 pi]).Step: 2 ：The sine function reaches its minimum value of -1 at (x = frac{3pi}{2}) in the interval ([0, 2pi]).Step: 3 ：Therefore, the value of (x) that satisfies the equation (sin x = -1) is (x = frac{3pi}{2}).Step: 4 ：Converting (frac{3pi}{2}) to decimal form gives approximately 4.71238898038469.Step: 5 ：Final Answer: The value of (x) that satisfies the equation (sin x = -1) in the interval ([0, 2pi]) is (boxed{frac{3pi}{2}}).

If $\sin x=-1$ and $x \in[0,2 \pi]$, the value of $x$ is

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