Problem

$\lim _{x \rightarrow-1} \frac{x^{4}+2 x^{3}+x^{2}}{x+1}=$

Answer

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Answer

\(\boxed{0}\)

Steps

Step 1 :Factor the numerator: $x^{4}+2x^{3}+x^{2} = x^{2}(x+1)^{2}$

Step 2 :Cancel out the (x+1) term in both the numerator and the denominator: $\frac{x^{2}(x+1)^{2}}{x+1} = x^{2}(x+1)$

Step 3 :Evaluate the limit as x approaches -1: $\lim_{x \rightarrow -1} x^{2}(x+1) = 0$

Step 4 :\(\boxed{0}\)

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