olve the following inequality.
\[
2 x^{\frac{2}{3}} \leq-4
\]
All real numbers.
$-2.828 \leq x \leq 2.828$
There is no solution.
$x \leq-2.828$ or $x \geq 2.828$

Answer

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Answer

Final Answer: $\boxed{\text{No Solution}}$

Steps

Step 1 ：The inequality is $2x^{2/3} \leq -4$.

Step 2 ：Isolate $x^{2/3}$ by dividing both sides by 2 to get $x^{2/3} \leq -2$.

Step 3 ：Since $x^{2/3}$ is always non-negative for real $x$, it cannot be less than or equal to -2.

Step 4 ：Therefore, there is no solution to this inequality.

Step 5 ：Final Answer: $\boxed{\text{No Solution}}$