Find polar coordinates of the point that has rectangular coordinates $(-3 \sqrt{3}, 3)$. Write your answer using degrees.

Step 1 ：The rectangular coordinates of the point are given as $(-3 \sqrt{3}, 3)$.

Step 2 ：We can find the polar coordinates $(r, \theta)$ of this point using the formulas $r = \sqrt{x^2 + y^2}$ and $\theta = \arctan(\frac{y}{x})$.

Step 3 ：Substituting the given values into the formula for $r$, we get $r = \sqrt{(-3 \sqrt{3})^2 + 3^2} = 6$.

Step 4 ：Substituting the given values into the formula for $\theta$, we get $\theta = \arctan(\frac{3}{-3 \sqrt{3}})$. However, since the point is in the second quadrant, we need to add 180 degrees to the result of the arctangent function, giving us $\theta = 150$ degrees.

Step 5 ：Therefore, the polar coordinates of the point $(-3 \sqrt{3}, 3)$ are $(6, 150^\circ)$.

Step 6 ：Final Answer: \(\boxed{(6, 150^\circ)}\)