What is the doubling time for the function $f(x)=9(1.2)^{x}$ ?
8.25
3.802
1.44
12.96
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Answer

So, the doubling time for the function $f(x)=9(1.2)^{x}$ is approximately $\boxed{3.802}$.

Steps

Step 1 ：The doubling time for an exponential function is given by the formula T = ln(2)/ln(b), where b is the base of the exponential function.

Step 2 ：In this case, b = 1.2.

Step 3 ：So, we need to calculate T = ln(2)/ln(1.2).

Step 4 ：Using the formula, we get T = 3.8017840169239308.

Step 5 ：So, the doubling time for the function $f(x)=9(1.2)^{x}$ is approximately $\boxed{3.802}$.