If the equilibrium constant for the reaction $C \rightleftharpoons D$ is 0.15 , what is the value of the equilibrium constant for the reaction $D \rightleftharpoons C$ ?

Step 1 ：The equilibrium constant for the reaction \(C \rightleftharpoons D\) is given as 0.15.

Step 2 ：The equilibrium constant for a reaction is the reciprocal of the equilibrium constant for the reverse reaction.

Step 3 ：Therefore, the equilibrium constant for the reaction \(D \rightleftharpoons C\) should be the reciprocal of 0.15.

Step 4 ：Calculate the reciprocal of 0.15 to find the equilibrium constant for the reaction \(D \rightleftharpoons C\).

Step 5 ：K_reverse = 1 / 0.15 = 6.666666666666667

Step 6 ：Round the result to two decimal places.

Step 7 ：K_reverse = 6.67

Step 8 ：Final Answer: The equilibrium constant for the reaction \(D \rightleftharpoons C\) is \(\boxed{6.67}\).