Problem

Use the method of polynomial division to find the remainder when \(3x^4 - 2x^3 + 7x^2 - 5x + 1\) is divided by \(x^2 - 3x + 1\).

Answer

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Answer

Step 6: Multiply the divisor \(x^2 - 3x + 1\) by \(-8\) and subtract the result from the new dividend. The result is \(16x - 7\), which is the remainder of the division.

Steps

Step 1 :Step 1: Perform the polynomial division, dividing the first term of the dividend \(3x^4\) by the first term of the divisor \(x^2\) gives us \(3x^2\).

Step 2 :Step 2: Multiply the divisor \(x^2 - 3x + 1\) by \(3x^2\) and subtract the result from the dividend. The result is \(-11x^3 + 20x^2 - 5x + 1\).

Step 3 :Step 3: Repeat the process, dividing the first term of the new dividend \(-11x^3\) by the first term of the divisor \(x^2\), which gives us \(-11x\).

Step 4 :Step 4: Multiply the divisor \(x^2 - 3x + 1\) by \(-11x\) and subtract the result from the new dividend. The result is \(-8x^2 + 28x - 11\).

Step 5 :Step 5: Repeat the process once more, dividing the first term of the new dividend \(-8x^2\) by the first term of the divisor \(x^2\), which gives us \(-8\).

Step 6 :Step 6: Multiply the divisor \(x^2 - 3x + 1\) by \(-8\) and subtract the result from the new dividend. The result is \(16x - 7\), which is the remainder of the division.

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