x^{2}+12 x-12 y+12=0

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Accepted Answer

Step:1 ：We are given the quadratic equation (x^{2}+12 x-12 y+12=0).Step:2 ：We can solve this equation using the quadratic formula, which is (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}), where a, b, and c are the coefficients of the quadratic equation in the form (ax^2 + bx + c = 0).Step:3 ：In this case, a = 1, b = 12, and c = -12y + 12.Step:4 ：Substituting these values into the quadratic formula, we get the solutions (x = -2sqrt{3y + 6} - 6) and (x = 2sqrt{3y + 6} - 6).Step:5 ：(boxed{x = -2sqrt{3y + 6} - 6, x = 2sqrt{3y + 6} - 6}) are the roots of the quadratic equation.

Answer

Step: 1 ：We are given the quadratic equation (x^{2}+12 x-12 y+12=0).Step: 2 ：We can solve this equation using the quadratic formula, which is (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}), where a, b, and c are the coefficients of the quadratic equation in the form (ax^2 + bx + c = 0).Step: 3 ：In this case, a = 1, b = 12, and c = -12y + 12.Step: 4 ：Substituting these values into the quadratic formula, we get the solutions (x = -2sqrt{3y + 6} - 6) and (x = 2sqrt{3y + 6} - 6).Step: 5 ：(boxed{x = -2sqrt{3y + 6} - 6, x = 2sqrt{3y + 6} - 6}) are the roots of the quadratic equation.

$x^{2}+12 x-12 y+12=0$

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