Listed below are body temperatures from five different subjects measured at $8 \mathrm{AM}$ and again at $12 \mathrm{AM}$. Find the values of $\bar{d}$ and $s_{d}$. In general, what does $\mu_{d}$ represent?
\begin{tabular}{lllllll}
\hline Temperature $\left({ }^{\circ} \mathrm{F}\right.$ ) at $8 \mathrm{AM}$ & 97.5 & 98.7 & 97.4 & 97.8 & 97.3 \\
\hline Temperature $\left({ }^{\circ} \mathrm{F}\right.$ ) at 12 AM & 98.4 & 98.9 & 97.9 & 97.7 & 97.6 \\
\hline
\end{tabular}
Let the temperature at $8 \mathrm{AM}$ be the first sample, and the temperature at $12 \mathrm{AM}$ be the second sample. Find the values of $\bar{d}$ and $s_{d}$.
\[
\overline{\mathrm{d}}=-0.36
\]
(Type an integer or a decimal. Do not round.)
\[
s_{d}=
\]
(Round to two decimal places as needed.)

Step 1 ：Given two sets of temperatures measured at 8 AM and 12 AM, we are asked to find the mean difference and the standard deviation of the differences.

Step 2 ：The mean difference, denoted as \(\bar{d}\), is calculated by subtracting each temperature at 8 AM from the corresponding temperature at 12 AM, summing these differences, and then dividing by the number of differences.

Step 3 ：The standard deviation of the differences, denoted as \(s_{d}\), is a measure of the amount of variation or dispersion of the set of differences. It is calculated by subtracting each difference from the mean difference, squaring the result, summing these squared results, dividing by the number of differences minus 1, and then taking the square root of the result.

Step 4 ：By performing these calculations, we find that the mean difference \(\bar{d}\) is approximately 0.36 and the standard deviation of the differences \(s_{d}\) is approximately 0.37.

Step 5 ：Thus, the values of \(\bar{d}\) and \(s_{d}\) are \(\boxed{0.36}\) and \(\boxed{0.37}\) respectively.