Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is $5 \mathrm{~L}$, the pressure is $424 \mathrm{kPa}$ (kilopascals).
Espanol What is the volume when the pressure is $265 \mathrm{kPa}$ ?
Answer
Final Answer: The volume of the gas when the pressure is 265 kPa is \(\boxed{8.0 L}\).
Step 1 ：Boyle's Law states that the product of the pressure and volume for a gas is a constant for a fixed amount of gas at a fixed temperature. This can be written in mathematical terms as \(PV = k\), where \(P\) is the pressure of the gas, \(V\) is the volume of the gas, and \(k\) is a constant.
Step 2 ：We are given that the volume \(V1\) is 5 L when the pressure \(P1\) is 424 kPa. We can find the constant \(k\) by calculating \(P1 * V1\).
Step 3 ：Substituting the given values, we get \(k = 424 * 5 = 2120\).
Step 4 ：We can find the volume \(V2\) when the pressure \(P2\) is 265 kPa by rearranging the formula to \(V2 = k / P2\).
Step 5 ：Substituting the values, we get \(V2 = 2120 / 265 = 8.0\).
Step 6 ：Final Answer: The volume of the gas when the pressure is 265 kPa is \(\boxed{8.0 L}\).
