Problem

Unit test
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This table gives a few \( (x, y) \) pairs of a line in the coordinate plane.
\( \begin{array}{cc}x & y \\ 34 & -52 \\ 51 & -65 \\ 68 & -78\end{array} \)
What is the \( y \)-intercept of the line?

Answer

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Answer

y - intercept: x = 0, y = -52 + \frac{-13}{17}(0 - 34)

Steps

Step 1 :\(m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-65 - (-52)}{51 - 34} = \frac{-13}{17}\)

Step 2 :\(y - (-52) = \frac{-13}{17}(x - 34)\)

Step 3 :y - intercept: x = 0, y = -52 + \frac{-13}{17}(0 - 34)

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