Find the terminal point on the unit circle determined by $\frac{11 \pi}{6}$ radians.
Use exact values, not decimal approximations.
\[
(x, y)=
\]
Answer
Final Answer: \(\boxed{(x, y)= \left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)}\)
Step 1 ：The terminal point on the unit circle determined by an angle in standard position is given by the coordinates (cos(θ), sin(θ)). In this case, the angle is \(\frac{11 \pi}{6}\) radians. So, we need to find the cosine and sine of this angle.
Step 2 ：The cosine and sine values are approximately 0.866 and -0.5 respectively. However, the question asks for exact values. The cosine and sine of \(\frac{11 \pi}{6}\) radians are exactly \(\frac{\sqrt{3}}{2}\) and \(-\frac{1}{2}\) respectively.
Step 3 ：Final Answer: \(\boxed{(x, y)= \left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)}\)
