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As a certain engine's rotation speed increases, its temperature increases at a constant rate.
The table compares the engine's rotation speed (in cycles per second) and its temperature (in degrees Celsius).
\begin{tabular}{|cc|}
\hline Rotation (cycles per second) & Temperature (degrees Celsius) \\
\hline 11 & 23.8 \\
13 & 25.4 \\
15 & 27 \\
\hline
\end{tabular}
What is the increase in temperature that comes with an increase of 1 cycle per second in the rotation?
degrees Celsius
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Do 4 problems
Answer
\( m = \frac{3.2}{4} = 0.8 \)
Step 1 ：\( \text{Find the slope (m)} = \frac{\Delta \text{Temperature}}{\Delta \text{Rotation}} \)
Step 2 ：\( m = \frac{27 - 23.8}{15 - 11} \)
Step 3 ：\( m = \frac{3.2}{4} = 0.8 \)
