Determine the remaining sides and angles of the triangle $A B C$.
\[
A=28.79^{\circ} \quad B=19.07^{\circ} \quad c=11.49 m
\]
\[
\mathrm{C}=
\]
\[
a \approx \square m
\]
m
(Round to the nearest hundredth as needed.)
(Round to the nearest hundredth as needed.)

Step 1 ：Given that in a triangle, the sum of angles is 180 degrees, we can calculate the third angle C as \(180 - A - B = 180 - 28.79 - 19.07 = 132.14^{\circ}\).

Step 2 ：We can then use the Law of Sines to find the remaining sides. The Law of Sines states that the ratio of the length of a side of a triangle to the sine of its opposite angle is the same for all three sides of the triangle. Therefore, we can write the following equations: \(\frac{a}{\sin A} = \frac{c}{\sin C}\) and \(\frac{b}{\sin B} = \frac{c}{\sin C}\).

Step 3 ：Solving these equations for a and b, we get \(a = c \cdot \frac{\sin A}{\sin C} \approx 7.46 m\) and \(b = c \cdot \frac{\sin B}{\sin C} \approx 5.06 m\).

Step 4 ：\(\boxed{C = 132.14^{\circ}, a \approx 7.46 m, b \approx 5.06 m}\)