\[
\tan ^{2} x-\sec ^{2} x
\]
chacse the carrect answer below
1
$\sec x$
$-1$
$-\cos ^{2} x$
Final Answer: \(\boxed{-1}\)
Step 1 :The given expression is \(\tan ^{2} x-\sec ^{2} x\).
Step 2 :We know that \(\tan ^{2} x = \sec ^{2} x - 1\) and \(\sec ^{2} x = \tan ^{2} x + 1\).
Step 3 :We can substitute \(\tan ^{2} x\) with \(\sec ^{2} x - 1\) in the given expression.
Step 4 :The simplified expression is -1. This means that \(\tan ^{2} x-\sec ^{2} x = -1\).
Step 5 :Final Answer: \(\boxed{-1}\)