Solve the equation for exact solutions over the interval $\left[0^{\circ}, 360^{\circ}\right)$.
\[
2 \sqrt{3} \sin 2 \theta=-3
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is $\{\quad\}$.
(Type an integer or a decimal. Type your answer in degrees. Do not include the degree symbol in your answe
B. The solution is the empty set.

Step 1 ：Given the equation \(2 \sqrt{3} \sin 2 \theta=-3\).

Step 2 ：Isolate \(\sin 2 \theta\) on one side of the equation to get \(\sin 2 \theta = -0.8660254037844387\).

Step 3 ：Use the arcsin function to solve for \(2 \theta\). The solution for \(2 \theta\) is \(-30^{\circ}\).

Step 4 ：Since the range of the arcsin function is \([-\pi/2, \pi/2]\) (or \([-90^{\circ}, 90^{\circ}]\) in degrees), we need to consider additional solutions in the interval \([0^{\circ}, 360^{\circ})\) by adding or subtracting \(360^{\circ}\) to the solutions.

Step 5 ：Add \(360^{\circ}\) to the solution \(-30^{\circ}\) to bring it into the desired interval. The solution for \(2 \theta\) is now \(330^{\circ}\).

Step 6 ：Finally, divide the solutions by 2 to solve for \(\theta\). The solution set is \(\boxed{330}\).